Question

5x(1-2x)-3x(x+18)=0

Answer 1

\(5x\left(1-2x\right)-3x\left(x+18\right)=0\)

\(\Leftrightarrow5x-10x^2-3x^2-54x\)

\(\Leftrightarrow-13x^2-49x=0\)

\(\Leftrightarrow x\left(-13x-49\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\-13x=49\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{49}{13}\end{matrix}\right.\)

Vậy ..

Answer 2

\(5x\left(1-2x\right)-3x\left(x+18\right)=0\)

=>\(5x-10x^2-3x^2-54x=0\)

=> \(-49x-13x^2=0\)

=> \(x\left(-49-13x\right)=0\)

=> \(\left[{}\begin{matrix}x=0\\-49-13x=0\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}x=0\\-49=13x\end{matrix}\right.\)

=> \(\left[{}\begin{matrix}x=0\\x=\dfrac{-49}{13}\end{matrix}\right.\)

Vậy \(x\in\left\{\dfrac{-49}{13};0\right\}\)

Answer 3

<=> 5x - 10x² - 3x² -54x = 0

<=> -13x² - 49x =0

<=> -x. (13x + 49) = 0

<=> \(\begin{matrix}-x=0\\13x+49=0\end{matrix}\)

<=> \(\begin{matrix}x=0\\x=-\dfrac{49}{13}\end{matrix}\)

=> đáp số .....

Answer 4

tick nha