a)
\(5x-3=4x+6\)
\(\Rightarrow5x-4x=6+3\)
=> x = 9
Vậy x = 9
b)
\(7-2x=4x-67\)
\(\Rightarrow7+67=4x+2x\)
\(\Rightarrow6x=74\)
\(\Rightarrow x=\frac{37}{2}\)
Vậy x = 37 / 2
*5x -3 = 4x + 6
5x - 4x = 6 + 3
=> x = 9
Vậy x = 9.
*7 - 2x = 4x - 67
7 + 67 = 4x + 2x
74 = 6x
=> x = 37/3
Vậy x = 37/3.
5x-3 =4x +6
=> 5x- 4x =3+6
=> x=9
7- 2x =4x -67
-2x-4x = -7-67
-6x = -74
=>x = -74/64
= 37/2