Question

( 4x- 8 )¹⁰

Answer 1

mk mới đọc sơ thôi ; không biết giải đúng hay sai ; mong mấy bạn đừng nép đá nha

ta có : \(\left(4x-8\right)^{10}=C^0_{10}\left(4x\right)^{10}+C^1_{10}\left(4x\right)^9\left(-8\right)+C^2_{10}\left(4a\right)^8\left(-8\right)^2+C^3_{10}\left(4a\right)^7\left(-8\right)^3+C^4_{10}\left(4a\right)^6\left(-8\right)^4+C^5_{10}\left(4a\right)^5\left(-8\right)^5+C^6_{10}\left(4a\right)^4\left(-8\right)^6+C^7_{10}\left(4a\right)^3\left(-8\right)^7+C^8_{10}\left(4a\right)^2\left(-8\right)^8+C^9_{10}\left(4a\right)\left(-8\right)^9+C^{10}_{10}\left(-8\right)^{10}\)