4) \(n_{SO2}=\frac{1,344}{22,4}=0,06\left(mol\right)\)
\(n_{KOH}=0,02.2=0,04\left(mol\right)\)
\(\frac{n_{KOH}}{n_{SO2}}=\frac{0,04}{0,06}=\frac{2}{3}\)
=> Tạo 1 muối axit
\(KOH+SO2-->KHSO3\)
\(n_{KHSO3}=n_{KOH}=0,04\left(mol\right)\)
\(m_{KHSO3}=0,04.120=4,8\left(g\right)\)
5) \(n_{SO2}=\frac{4,48}{22,4}=0,2\left(mol\right)\)
\(n_{NaOH}=0,15.2=0,3\left(mol\right)\)
\(\frac{n_{NaOH}}{n_{SO2}}=\frac{0,3}{0,2}=1,5\)
=> Tạo 2 muối
\(SO2+KOH-->NaHSO3\)
x-----------x--------------------x(mol)
\(SO2+2KOH-->Na2SO3+H2O\)
y-----------2y---------------y(mol)
theo bài ta có hpt
\(\left\{{}\begin{matrix}x+y=0,2\\x+2y=0,3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,1\\y=0,1\end{matrix}\right.\)
\(m_{NaHSO3}=0,1.104=10,4\left(g\right)\)
\(m_{Na2SO3}=0,1.126=12,6\left(g\right)\)
6) \(n_{SO2}=\frac{12,8}{64}=0,2\left(mol\right)\)
\(n_{NaOH}=0,25.1=0,25\left(mol\right)\)
\(\)\(\frac{n_{NaOH}}{n_{SO2}}=\frac{0,25}{0,2}=1,25\)
=>Tạo 2 muối
\(SO2+KOH-->NaHSO3\)
x------------x--------------x(mol)
\(SO2+2KOH-->Na2SO3+H2O\)
y----------2y-------------------y(mol)
Theo bài ta có hpt
\(\left\{{}\begin{matrix}x+y=0,2\\x+2y=0,25\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,15\\y=0,05\end{matrix}\right.\)
\(m_{NaHSO3}=0,15.104=15,6\left(g\right)\)
\(m_{Na2SO3}=0,05.126=6,3\left(g\right)\)
