\(\dfrac{3x+2}{x-1}=3\left(x\ne1\right)\)
suy ra
`3x+2=3(x-1)`
`<=>3x+2=3x-3`
`<=> 3x-3x=-3-2`
`<=> 0x=-5` (vô lí vì 0x=0 với mọi x)
\(\dfrac{3x+2}{x-1}=3\) (ĐK: x ≠ 1)
\(\Leftrightarrow3x+2=3\left(x-1\right)\)
\(\Leftrightarrow3x+2=3x-3\)
\(\Leftrightarrow3x-3x=-3-2\)
\(\Leftrightarrow0x=-5\) (Vô lí)
Vậy \(S=\varnothing\).
\(\dfrac{3x+2}{x-1}=3\) \(\left(dkxd:x\ne1\right)\)
\(\Leftrightarrow3x+2=3\left(x-1\right)\)
\(\Leftrightarrow3x+2=3x-3\)
\(\Leftrightarrow3x-3x=-3-2\)
\(\Leftrightarrow0=-5\left(VL\right)\)
Vậy \(S=\varnothing\)