\(\dfrac{31}{2}\)-2x.\(\dfrac{11}{5}\)=\(\dfrac{71}{3}\)
=> 2x.\(\dfrac{11}{5}\)=\(\dfrac{31}{2}\)-\(\dfrac{71}{3}\)
2x.\(\dfrac{11}{5}\)=\(\dfrac{-49}{6}\)
2x=\(\dfrac{-49}{6}\):\(\dfrac{11}{5}\)
2x=\(\dfrac{-245}{66}\)
x=\(\dfrac{-245}{66}\):2
x=\(\dfrac{-245}{132}\)
Vậy x =\(\dfrac{-245}{132}\).