Vì \(\left(2x+1\right)\left(y-2\right)=10\)
\(\Rightarrow\left\{{}\begin{matrix}2x+1\\y-2\end{matrix}\right.\inƯ\left(10\right)\)
\(Ư\left(10\right)=\left\{1;2;5;10\right\}\)
\(\Rightarrow\left\{{}\begin{matrix}\left\{{}\begin{matrix}2x+1=1\Rightarrow x=0\\y-2=10\Rightarrow y=12\end{matrix}\right.\\\left\{{}\begin{matrix}2x+1=2\Rightarrow x=0,5\\y-2=5\Rightarrow y=7\end{matrix}\right.x\notin N\left(loai\right)\\\left\{{}\begin{matrix}2x+1=5\Rightarrow x=2\\y-2=2\Rightarrow y=4\end{matrix}\right.\\\left\{{}\begin{matrix}2x+1=10\Rightarrow x=4,5\\y-2=1\Rightarrow y=3\end{matrix}\right.x\notin N\left(loai\right)\end{matrix}\right.\)
Vậy \(\left(x;y\right)\in\left\{\left(0;12\right),\left(2;4\right)\right\}\)
