Bài 1: Tìm x:
a) \(\frac{6x+5}{2}-\left(2x+\frac{2x+1}{2}\right)=\frac{10x+3}{4}\)
b) \(\frac{3.\left(2x+1\right)}{4}-\frac{5x+3}{6}+\frac{x+1}{3}=x+\frac{7}{12}\)
GIÚP MIK NHA!! MIK ĐAG CẦN GẤP
\(\frac{3}{2}x\)---\(\frac{2}{5}\)= \(\frac{1}{3}\)x\(\frac{1}{3}x\) --- \(\frac{1}{4}\)
2/ 2x --\(\frac{1}{4}\)= \(\frac{5}{6}\)--- \(\frac{1}{2}x\)
3/ \(-\frac{5}{6}\)+ 3x = \(\frac{2}{3}\)--- \(\frac{1}{2}x\)
4/ \(\frac{5}{3}\)[ 3x --- 3 ] + \(\frac{1}{2}\)= \(\frac{1}{2}\)[ 2x ---- 1 ]
Tìm x, biết
a) \(\frac{3}{2}x-\frac{7}{3}=-\frac{1}{4}\)
b) \(\frac{3}{4}-\left(x+\frac{1}{2}\right)=\frac{1}{4}\)
c) \(\left|2x-1\right|-\frac{1}{2}=\frac{1}{3}\)
Tìm x : \(\left|\frac{3}{4}+\frac{1}{4}:x\right|=\frac{2}{5}\)
b) \(\frac{2}{3}x-1\frac{2}{5}=\frac{1}{2}x+0,8\)
c) \(\left|2x-1\right|-x=1\)
Tìm x biết:
a) 3 : (1 - \(\frac{3}{2}\)x) = 4 : (2 - x)
b) \(\frac{-1}{7}\) . 23 - 2x : 1\(\frac{4}{3}\) = -2x-1
c) 2.3x + 3x-1 = 7(32 + 2.62)
d) 2x - \(\frac{5}{4}\) = (3 - \(\frac{1}{2}\))(x - \(\frac{1}{2}\))
e) \(\frac{1}{2}\) . 2x + 2x+2 = 28 . 25
tìm x , y , z biết
a,
\(\frac{x+y}{x}=\frac{y}{x+z}=\frac{z}{x+y}=x+y+z\)
b,
\(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+3y-1}{6x}\)
c,
\(\frac{1+3y}{12}=\frac{1+6y}{2x}=\frac{1+9y}{5x}\)
d,
\(\frac{y+z+1}{x}=\frac{z+x+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\)
Bài 1: Tìm x biết:
a, \(x.\cdot\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)
b, \(\left(5x-1\right).\left(2x-\frac{1}{3}\right)=0\)
c, \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
d, \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\)
e, \(\frac{-3}{4}-\left|\frac{4}{5}-x\right|=-1\)
Tìm các số x, y, z biết rằng:
a) \(\frac{y+z+1}{x}=\frac{x+y+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\);
b) \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\);
c) \(\frac{2x+1}{5}=\frac{3y-2}{7}=\frac{2x+3y-1}{6x}\)
Bài 1: Tìm x:
a, \(\frac{7-x}{2}-\frac{2x-3}{4}=\frac{x+2}{8}-\frac{-1}{2}\)
b, \(x^2-4x+3=0\)
tìm GTNN của biểu thức:
P = \(\left[{}\left(\frac{-1}{3}\right)^2}x^3+\left(2x^2\right)^2+\frac{1}{2}]-\left[{}x\left(\frac{1}{3}x\right)^2+\begin{matrix}3\\2^3\end{matrix}\right.+x^4]+\left(y-2013\right)^2\)