a)
\(2x+5.11^0=3^2\)
<=>\(2x+5.1=3^2\)
<=> \(2x=9-5\)
<=> \(2x=4\)
<=> \(x=2\)
Vậy x=2
b)
\(4.\left(3x-13\right)=\dfrac{64}{2^3}\)
<=> \(4\left(3x-13\right)=\dfrac{64}{8}\)
<=> \(4.\left(3x-13\right)=8\)
<=> \(3x-13=2\)
<=> \(3x=15\)
<=> \(x=5\)
Vậy x=5