Ta có: 2x-(17-x)=x-9
=>2x-17+x=x-9
=>2x-17+x-x+9=0
=>2x-8=0
=>2x =8
=>x =4
Ta có: \(2x-\left(17-x\right)=x-9\)
\(\Rightarrow2x-17+x=x-9\)
\(\Rightarrow2x-17+x-x+9=0\)
\(\Rightarrow2x-8=0\)
\(\Rightarrow2x=8\)
\(\Rightarrow8:2\)
\(\Rightarrow x=4\)
Ta có: 2x-(17-x)= x-9
=>2x-17+x = x-9
=>2x-17+x+x+9=0
=>2x-8 =0
=>2x =8
=>x =4