Question

 2x + 10 ⋮ x + 3

Answer 1

\(\frac{2x+10}{x+3}=\frac{2\left(x+3\right)+4}{x+3}=2+\frac{4}{x+3}\)

Vậy để \(2x+10⋮x+3\) thì \(x+3\inƯ\left(4\right)\)

Mà Ư(4)={1;-1;2;-2;4;-4}

=>x+3={1;-1;2;-2;4;-4}

Ta có bẳng sau:

x+3	1	-1	2	-2	4	-4
x	-2	-4	-1	-5	1	-7

Vậy x={-2;-4;-1;-5;1;-7} 

 

Answer 2

\(2x+10⋮x+3\\ \Rightarrow2\left(x+3\right)+4⋮x+3\\ \Rightarrow4⋮x+3\\ \Rightarrow x+3\in\text{Ư}\left(4\right)=\left\{1;2;4;-1;-2;-4\right\}\\ x\in\left\{-2;-1;1;-4;-5;-7\right\}\)