\(2^{n+2}.2=64\)
\(\Rightarrow2^{n+2}=32\)
\(\Rightarrow2^n.2^2=32\)
\(\Rightarrow2^n=8\)
\(\Rightarrow2^n=2^3\Leftrightarrow n=3\)
\(2^{n+2}.2=64\)
\(2^{n+2}=64\div2\)
\(2^{n+2}=32=2^4\)
\(\Rightarrow n+2=4\)
\(\Rightarrow n=2\)
2n+2.2 = 64
=> 2n+2 = 64.2
=> 2n+2 = 128
=> 2n.22 = 128
=> 2n.4 = 128
=> 2n = 32
=> 2n = 25
=> n = 5