Question

2mu x +1 +5nhan 2 mu x +2 =88

Answer 1

\(2^{x+1}+5.2^{x+2}=88\)

\(\Rightarrow2^x.2+5.2^x.2^2=88\)

\(\Rightarrow2^x\left(2+5.2^2\right)=88\)

\(\Rightarrow2^x.22=88\)

\(\Rightarrow2^x=4\)

\(\Rightarrow2^x=2^2\)

\(\Rightarrow x=2\)

Vậy x = 2

Answer 2

Theo bài ra ta có:

2^x+1+5.2^x+2 = 88

=> 2^x.2+5.2^x.2²

=> 2^x.( 2 = 5.2² )

=> 2^x.22 = 88

=> 2^x = 88:22

=> 2^x = 4

=> x = 4:2

=> x = 2

Vậy x = 2

Answer 3

2^x+1+5.2^x+2=88

2^x+1+5.2^x+1.2=88

2^x+1+(5.2).2^x+1=88

2^x+1+10.2^x+1 =88

2^x+1(1+10) =88

2^x+1.11 =88

2^x+1 =88:11

2^x+1 =8

2^x+1 =2³

x+1 =3

x =3-1

x = 2

Vậy x=2