Question

2014mu 0 +(-5)+2010

(4 7/13 +6/13) mu 3

(-2/3)mu 2015*x=(-2/3)mu 2017

Answer 1

a: \(2014^0+\left(-5\right)+2010=1-5+2010=2006\)

b: \(=\left(4+\dfrac{7}{13}+\dfrac{6}{13}\right)^3=5^3=125\)

c: \(\left(-\dfrac{2}{3}\right)^{2015}\cdot x=\left(-\dfrac{2}{3}\right)^{2017}\)

\(\Leftrightarrow x=\left(-\dfrac{2}{3}\right)^{2017}:\left(-\dfrac{2}{3}\right)^{2015}=\left(-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\)