(3/7)20/(9/49)5=(3/7)20/(32/72)5=(3/7)20(3/7)10=(3/7)10
\(\dfrac{\left(\dfrac{3}{7}\right)^{20}}{\dfrac{9}{49}^5}=\dfrac{\left(\dfrac{3}{7}\right)^{20}}{\left(\dfrac{3}{7}\right)2^5}=\dfrac{\left(\dfrac{3}{7}\right)20}{\left(\dfrac{3}{7}\right)^{10}}=\dfrac{3}{7}^{10}\)