1/
\(d_{\dfrac{N_2}{CO_2}}=\dfrac{M_{N_2}}{M_{CO_2}}=\dfrac{28}{44}\approx0,64\)
\(d_{\dfrac{N_2}{KK}}=\dfrac{M_{N_2}}{M_{KK}}=\dfrac{28}{29}\approx0,97\)
2/
\(M_{Na_2SO_4}=23.2+32+16.4=142\left(\dfrac{g}{mol}\right)\)
%Na=\(\dfrac{23.2}{142}.100\%\approx32,4\%\)
%S=\(\dfrac{32}{142}.100\%\approx22,54\%\)
%O=100%-32,4%-22,54%=45,06%
3/
\(n_{Na}=\dfrac{3.10^{24}}{6.10^{23}}=5mol\)
\(m_{Na}=5.23=115gam\)