=> \(315+146-x=401\)
\(=>461-x=401\)
\(=>x=461-401\)
\(=>x=60\)
CHÚC BẠN HỌC TỐT...............
Ta có: \(315+\left(146-x\right)=401\)
\(\Rightarrow146-x=401-315\)
\(\Rightarrow-x=401-315-146\)
\(\Rightarrow-x=-60\)
\(\Rightarrow x=60\)
Vậy \(x=60\)
Ta có :
315 + ( 146 - x ) = 401
146 - x = 401 - 315
146 - x = 86
x = 146 - 86
x = 60
Vậy x = 60
\(a,315+\left(146-x\right)=401\\ 146-x=401-315\\ 146-x=86\\ x=146-86\\ x=60\)
Học tốt !!!
a) Ta có: \(315+\left(146-x\right)=401\)
\(\Leftrightarrow315+164-x=401\)
\(\Rightarrow-x=401-315-164\)
\(\Rightarrow-x=-68\)
\(\Rightarrow x=68\)
Vậy \(x=68\)