1)
2KMnO4---->K2MnO4 +MnO2 +O2
Ta có
n\(_{KMnO4}=\)\(\frac{4,74}{158}=0,03\left(mol\right)\)
Theo pthh
n\(_{K2MnO2}=\frac{1}{2}n_{KMnO2}=0,015\left(mol\right)\)
m\(_{K2MnO2}=0,015.197=2,955\left(g\right)\)
Theo pthh
n\(_{MnO2}=\frac{1}{2}n_{KMnO2}=0,015\left(mol\right)\)
m\(_{MnO2}=0,015.87=1,305\left(g\right)\)