a : 3 dư 1 \(\Rightarrow a=3k_1+1\left(k_1\ge0\right)\left(1\right)\)
b : 3 dư 2 \(\Rightarrow b=3k_2+2\left(k_2\ge0\right)\left(2\right)\)
Từ (1) ; (2)
\(\Rightarrow ab=\left(3k_1+1\right)\left(3k_2+2\right)\)
\(\Rightarrow ab=9k_1k_2+6k_1+3k_2+2\)
\(\Rightarrow ab=3\left(3k_1k_2+2k_1+k_2\right)+2\)
\(\Rightarrow ab:3\) dư 2 ( đpcm )