CO2 + Ba(OH)2 → BaCO3↓ + H2O
\(n_{CO_2}=\frac{2,24}{22,4}=0,1\left(mol\right)\)
Theo PT: \(n_{Ba\left(OH\right)_2}=n_{CO_2}=0,1\left(mol\right)\)
\(\Rightarrow C_{M_{Ba\left(OH\right)_2}}=\frac{0,1}{0,2}=0,5\left(M\right)\)
The PT: \(n_{BaCO_3}=n_{CO_2}=0,1\left(mol\right)\)
\(\Rightarrow m_{BaCO_3}=0,1\times197=19,7\left(g\right)\)