Question

1.

a) \(\left(0,4\right)^2+3x=\left(0,5\right)^2\)

b) \(2\left(x-4\right)-\left(\dfrac{2}{5}+\dfrac{8}{5}-\dfrac{1}{6}\right)=\dfrac{1}{6}-\dfrac{2}{5}\)

c) \(\left|2x-1\right|=5\)

Answer 1

\(1,a,0,16+3x=0,25\\ 3x=0,09\\ x=0,03\\ b,2\left(x-4\right)-\left(\dfrac{2.6-1}{6}\right)=-\dfrac{7}{30}\\ 2\left(x-4\right)-\dfrac{11}{6}=-\dfrac{7}{30}\\ 2\left(x-4\right)=\dfrac{8}{5}\\ x-4=\dfrac{4}{5}\\ x=\dfrac{24}{5}\\ c,\left[{}\begin{matrix}2x-1=5\\2x-1=-5\end{matrix}\right.=>\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)

Answer 2

`1.`

`a) 3x=(0,25-0,16)=0,09`

`x=0,09/3=0,03`

`b) 2(x-4)-11/6=(-7)/30`

`=> x-4=8/5 :2`

`=> x=24/5`

`c)` \(\left[\begin{array}{} 2x-1=5\\ 2x-1=-5 \end{array} \right.\)

`=>`\(\left[\begin{array}{} 2x=6\\ 2x=-4 \end{array} \right.\)

`=>`\(\left[\begin{array}{} x=3\\ x=-2 \end{array} \right.\)