$n_{CuCl_2} = \dfrac{13,6}{136} = 0,1(mol)$
$C_{M_{CuCl_2}} = \dfrac{0,1}{0,5} = 0,2M$
$m_{dd\ CuCl_2} = D.V = 1,12.500 = 560(gam)$
$C\%_{CuCl_2} = \dfrac{13,6}{560}.100\% = 2,42\%$
n Cucl2=13,6\135=0,1 mol
m dd=1,12.500=560g
c%=13,6\560+13.6 .100=2,37%
Cm=0,1\0,5=0,2M