Số số hạng là: \(\dfrac{x-1}{2}+1=\dfrac{x-1+2}{2}=\dfrac{x+1}{2}\)
Tổng là:
\(\left(x+1\right)\cdot\dfrac{x+1}{2}=\dfrac{\left(x+1\right)^2}{2}\)
Theo đề, ta có: \(\left(x+1\right)^2=162\)
\(\Leftrightarrow\left[{}\begin{matrix}x=9\sqrt{2}-1\\x=-9\sqrt{2}-1\end{matrix}\right.\)