Số số hạng là (x-1):2+1(số)
Tổng là: \(\dfrac{\left(x+1\right)\cdot\left[\dfrac{1}{2}\left(x-1\right)+1\right]}{2}=\dfrac{1}{4}\left(x+1\right)\left(x-1\right)+\dfrac{1}{2}\left(x+1\right)\)
Theo đề, ta có: \(\dfrac{1}{4}\left(x+1\right)\left(x-1\right)+\dfrac{1}{2}\left(x+1\right)=36\)
\(\Leftrightarrow\left(x+1\right)\left(x-1\right)+2\left(x+1\right)=144\)
\(\Leftrightarrow x^2-1+2x+2-144=0\)
=>x2+2x-143=0
=>x=11