\(\dfrac{1}{3}\cdot\dfrac{-6}{13}\cdot\dfrac{-9}{10}\cdot\dfrac{-13}{36}=\dfrac{1}{3}\cdot\dfrac{-6}{13}\dfrac{-9}{10}\dfrac{-1}{2}=\dfrac{1\cdot\left(-6\right)\cdot\left(-9\right)\left(-1\right)}{3\cdot13\cdot10\cdot2}=\dfrac{-1\cdot2\cdot3\cdot-9}{3\cdot13\cdot10\cdot2}=\dfrac{9}{130}\)