\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{12}=\dfrac{4}{12}+\dfrac{2}{12}+\dfrac{1}{12}=\dfrac{7}{12}\)
\(=\dfrac{4}{12}+\dfrac{2}{12}+\dfrac{1}{12}=\dfrac{7}{12}\)
\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{12}=\dfrac{4}{12}+\dfrac{2}{12}+\dfrac{1}{12}=\dfrac{7}{12}\)