Ta có: \(12\cdot\left|x-1\right|:3=4^3+2^3\)
\(\Leftrightarrow\dfrac{12\left|x-1\right|}{3}=64+8=72\)
\(\Leftrightarrow4\left|x-1\right|=72\)
\(\Leftrightarrow\left|x-1\right|=18\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=18\\x-1=-18\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=19\\x=-17\end{matrix}\right.\)
Vậy: \(x\in\left\{19;-17\right\}\)
\(12|x-1|:3=4^3+2^3\)
\(12|x-1|:3=64+8\)
\(12|x-1|:3=72\)
\(12|x-1|=72.3\)
\(12|x-1|=216\)
\(|x-1|=216:12\)
\(|x-1|=18\)
\(\Rightarrow x-1 \in \{18;-18\}\)
\(\Rightarrow x \in \{19;-17\}\)
-Vậy \( x \in \{19;-17\}\)
