Question

1. Tìm \(x\)

a,\(\left(5876321-999999-3876000-322\right):x=5\)

b,\(\left(7593-1997\right).x+\dfrac{1,1}{x}-5696.x=\dfrac{1,1}{x}\)

Answer 1

a. \(\left(5876321-999999-3876000-322\right):x=5\)

\(\Rightarrow1000000:x=5\)

\(\Rightarrow5x=1000000\)

\(\Rightarrow x=\dfrac{1000000}{5}=200000\)

Vậy \(x=200000\)

b. \(\left(7593-1997\right)x+\dfrac{1,1}{x}-5696x=\dfrac{1,1}{x}\)

\(\Rightarrow5596x-5696x=\dfrac{1,1}{x}-\dfrac{1,1}{x}=0\)

\(\Rightarrow-100x=0\)

\(\Rightarrow x=0\)

Vậy \(x=0\)

Answer 2

a,$\left(5876321-999999-3876000-322\right):x=5$

$<=>\; 1000000:x=5$

$<=>x=200000.$

b,$\left(7593-1997\right).x+\frac{1,\mathrm{1/}}{x}-56$96x=1.1/x

<=>5596x + 1,1/x -5696x =1,1/x

<=> -100x =1,1/x -1,1/x

<=> -100x = 0

<=> x= 0