Ta có: \(8x^2-4x+1⋮2x+1\)
\(\Rightarrow\left(8x^2+4x\right)-\left(8x-1\right)⋮2x+1\)
\(\Rightarrow4x\left(2x+1\right)-\left(8x+4\right)+5⋮2x+1\)
\(\Rightarrow4x\left(2x+1\right)-4\left(2x+1\right)+5⋮2x+1\)
\(\Rightarrow\left(4x-4\right)\left(2x+1\right)+5⋮2x+1\)
\(\Rightarrow5⋮2x+1\)
\(\Rightarrow2x+1\in\left\{1;-1;5;-5\right\}\)
\(\Rightarrow x\in\left\{0;-1;2;-3\right\}\)
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