a,Gọi nCO2=a , nCO= b
Ta có : (44a+ 28b)/(a+b): 32=1
<=> (44a + 28b)/(a+b)=32
<=> 44a + 28b= 32a+ 32b
<=> 12a=4b
<=> 3a=b
=> %VCO= 3a.100/(a+3a)=75%
%VCO2=100-75=25%
b, Ta có 3a=b => mA= 44a + 84a=6,4
<=> a=0,05 mol
=> mCO2=0,05.44=2,2 g
mCO=6,4-2,2=4,2g