a) Ta có: \(\frac{x-3}{4}=\frac{2x+5}{3}\)
\(\Leftrightarrow\frac{x-3}{4}-\frac{2x+5}{3}=0\)
\(\Leftrightarrow\frac{3\left(x-3\right)}{12}-\frac{4\left(2x+5\right)}{12}=0\)
\(\Leftrightarrow3x-9-4\left(2x+5\right)=0\)
\(\Leftrightarrow3x-9-8x-20=0\)
\(\Leftrightarrow-5x-29=0\)
\(\Leftrightarrow-5x=29\)
hay \(x=\frac{29}{5}\)
Vậy: \(x=\frac{29}{5}\)
b) Ta có: \(\frac{x}{6}+\frac{x-2}{3}=0\)
\(\Leftrightarrow\frac{x}{6}+\frac{2\left(x-2\right)}{6}=0\)
\(\Leftrightarrow x+2\left(x-2\right)=0\)
\(\Leftrightarrow x+2x-4=0\)
\(\Leftrightarrow3x-4=0\)
\(\Leftrightarrow3x=4\)
hay \(x=\frac{4}{3}\)
Vậy: \(x=\frac{4}{3}\)
c) Ta có: \(\frac{x+5}{4}+2=\frac{3x-2}{6}\)
\(\Leftrightarrow\frac{3\left(x+5\right)}{12}+\frac{24}{12}-\frac{2\left(3x-2\right)}{12}=0\)
\(\Leftrightarrow3x+15+2x-2\left(3x-2\right)=0\)
\(\Leftrightarrow3x+15+2x-6x+4=0\)
\(\Leftrightarrow11-x=0\)
hay x=11
Vậy: x=11
d) Ta có: \(5x-2\left(3x-5\right)=7x+11\)
\(\Leftrightarrow5x-6x+10-7x-11=0\)
\(\Leftrightarrow-8x-1=0\)
\(\Leftrightarrow-8x=1\)
hay \(x=\frac{-1}{8}\)
Vậy: \(x=\frac{-1}{8}\)
