Question

1. | 4-2x | . 1/3 = 1/3
2. (-3)² : | x+(-1) | = (-3)
3. | 3/2 -x | + (-4/5) = -14/5
4. (-4/3) - | 2x + (-1) | = -7/3
5. -9 . | 36 - x/2 | = (-54)
6. 0,75 - | (-x) + 1/3 | = 0,25
7. (-6/5) + | x-9 |= (-6/5)
8. (-4) . | 3x - 1/5 | = 12

Answer 1

1) \(\left|4-2x\right|.\dfrac{1}{3}=\dfrac{1}{3}\)

\(\left|4-2x\right|=\dfrac{1}{3}:\dfrac{1}{3}\)

\(\left|4-2x\right|=\dfrac{1}{3}.3\)

\(\left|4-2x\right|=1\)

=>\(4-2x=\pm1\)

+)\(TH1:4-2x=1\) +)\(TH2:4-2x=-1\)

\(2x=4-1\) \(2x=4-\left(-1\right)\)

\(2x=3\) \(2x=4+1\)

\(x=3:2\) \(2x=5\)

\(x=1,5\) \(x=5:2\)

Vậy x=1,5 \(x=2,5\)

Vậy x=2,5

Answer 2

2) \(\left(-3\right)^2:\left|x+\left(-1\right)\right|=-3\)

\(9:\left|x+\left(-1\right)\right|=-3\)

\(\left|x+\left(-1\right)\right|=9:\left(-3\right)\)

\(\left|x+\left(-1\right)\right|=-3\)

=> \(x+\left(-1\right)\) sẽ không có giá trị nào ( Vì giá trị tuyệt đối luôn luôn lớn hơn hoặc bằng 0 )

Vậy x = \(\varnothing\)

Answer 3

3) \(\left|\dfrac{3}{2}-x\right|+\left(-\dfrac{4}{5}\right)=-\dfrac{14}{5}\)

\(\left|\dfrac{3}{2}-x\right|=\left(-\dfrac{14}{5}\right)-\left(-\dfrac{4}{5}\right)\)

\(\left|\dfrac{3}{2}-x\right|=\left(-\dfrac{14}{5}\right)+\dfrac{4}{5}\)

\(\left|\dfrac{3}{2}-x\right|=-\dfrac{10}{5}\)

\(\left|\dfrac{3}{2}-x\right|=-2\)

=> \(\dfrac{3}{2}-x\) không có giá trị nào thỏa mãn ( Vì giá trị tuyệt đối không thể là số nguyên âm )

Vậy x=\(\varnothing\)

Answer 4

Mấy câu sau bạn tự làm nha

Answer 5

4) \(\left(-\dfrac{4}{3}\right)-\left|2x+\left(-1\right)\right|=-\dfrac{7}{3}\)

\(\left|2x+\left(-1\right)\right|=\left(-\dfrac{4}{3}\right)-\left(-\dfrac{7}{3}\right)\)

\(\left|2x+\left(-1\right)\right|=\left(-\dfrac{4}{3}\right)+\dfrac{7}{3}\)

\(\left|2x+\left(-1\right)\right|=1\)

=> \(2x+\left(-1\right)=\pm1\)

+)\(TH1:2x+\left(-1\right)=1\) +)\(TH2:2x+\left(-1\right)=-1\)

\(2x=1-\left(-1\right)\) \(2x=\left(-1\right)-\left(-1\right)\)

\(2x=1+1\) \(2x=\left(-1\right)+1\)

\(2x=2\) \(2x=0\)

\(x=2:2\) \(x=0:2\)

\(x=1\) \(x=0\)

Vậy x=1 Vậy x=0

Answer 6

5) \(\left(-9\right).\left|36-\dfrac{x}{2}\right|=\left(-54\right)\)

\(\left|36-\dfrac{x}{2}\right|=\left(-54\right):\left(-9\right)\)

\(\left|36-\dfrac{x}{2}\right|=6\)

=> \(36-\dfrac{x}{2}=\pm6\)

+)\(TH1:36-\dfrac{x}{2}=6\) +)\(TH2:36-\dfrac{x}{2}=-6\)

\(\dfrac{x}{2}=36-6\) \(\dfrac{x}{2}=36-\left(-6\right)\)

\(\dfrac{x}{2}=30\) \(\dfrac{x}{2}=42\)

\(x=30.2\) \(x=42.2\)

\(x=60\) \(x=84\)

Vậy x=60 Vậy x=84

Answer 7

6) \(0,75-\left|\left(-x\right)+\dfrac{1}{3}\right|=0,25\)

\(\dfrac{3}{4}-\left|\left(-x\right)+\dfrac{1}{3}\right|=\dfrac{1}{4}\)

\(\left|\left(-x\right)+\dfrac{1}{3}\right|=\dfrac{3}{4}-\dfrac{1}{4}\)

\(\left|\left(-x\right)+\dfrac{1}{3}\right|=\dfrac{2}{4}\)

\(\left|\left(-x\right)+\dfrac{1}{3}\right|=\dfrac{1}{2}\)

Vì giá trị tuyệt đối luôn thuộc N , mà \(\dfrac{1}{2}\) lại là phân số nên \(\left(-x\right)+\dfrac{1}{3}\) không có giá trị của x

Vậy x=\(\varnothing\)

Answer 8

7)\(\left(-\dfrac{6}{5}\right)+\left|x-9\right|=-\dfrac{6}{5}\)

\(\left|x-9\right|=\left(-\dfrac{6}{5}\right)-\left(-\dfrac{6}{5}\right)\)

\(\left|x-9\right|=\left(-\dfrac{6}{5}\right)+\dfrac{6}{5}\)

\(\left|x-9\right|=1\)

=> \(x-9=\pm1\)

+)\(TH1:x-9=1\) +)\(TH2:x-9=-1\)

\(x=1+9\) \(x=\left(-1\right)+9\)

\(x=10\) \(x=8\)

Vậy x=10 Vậy x=8

Answer 9

8) \(\left(-4\right).\left|3x-\dfrac{1}{5}\right|=12\)

\(\left|3x-\dfrac{1}{5}\right|=12:\left(-4\right)\)

\(\left|3x-\dfrac{1}{5}\right|=-3\)

Vì giá trị tuyệt đối luôn luôn lớn hơn 0

=> Không có giá trị nào của x thỏa mãn

Vậy x=\(\varnothing\)

Answer 10

Tick mik nha