14: \(\left|-\dfrac{5}{3}\right|+\left(-\dfrac{11}{4}\right):\sqrt{\dfrac{1}{16}}-\left(\dfrac{20}{21}\right)^0\)
\(=\dfrac{5}{3}-\dfrac{11}{4}:\dfrac{1}{4}-1\)
\(=\dfrac{5}{3}-11-1=\dfrac{5}{3}-12=-\dfrac{31}{3}\)
15: \(2\dfrac{3}{5}-\dfrac{9}{5}\cdot\sqrt{\dfrac{1}{9}}+\left(-1\right)^{2020}+\left|-2021\right|\)
\(=\dfrac{13}{5}-\dfrac{9}{5}\cdot\dfrac{1}{3}+1+2021\)
\(=\dfrac{13}{5}-\dfrac{3}{5}+2022\)
=2+2022
=2024
16: \(\dfrac{2}{3}\cdot\sqrt{81}-\left(-\dfrac{3}{4}\right)\cdot\sqrt{\dfrac{9}{64}}+\left(\dfrac{\sqrt{2}}{3}\right)^2\)
\(=\dfrac{2}{3}\cdot9+\dfrac{3}{4}\cdot\dfrac{3}{8}+\dfrac{2}{9}\)
\(=6+\dfrac{9}{32}+\dfrac{2}{9}\)
\(=\dfrac{1873}{288}\)
17: \(4\dfrac{2}{3}-\dfrac{4}{3}\cdot\sqrt{\dfrac{1}{4}}+\left(-1\right)^{2021}+\left|-2020\right|\)
\(=\dfrac{14}{3}-\dfrac{4}{3}\cdot\dfrac{1}{2}+1+2020\)
\(=\dfrac{14}{3}-\dfrac{2}{3}+2021\)
=12/3+2021
=2021+4
=2025
18: \(\left(-\dfrac{1}{2}\right)^2:\dfrac{-1}{4}-2\cdot\left(-\dfrac{1}{2}\right)^3+\sqrt{25-16}\)
\(=\dfrac{1}{4}\cdot\dfrac{-4}{1}-2\cdot\dfrac{-1}{8}+\sqrt{9}\)
\(=-1+\dfrac{1}{4}+3\)
\(=2+\dfrac{1}{4}=\dfrac{9}{4}\)
19: \(\left(\dfrac{3}{2}\right)^2-\left[\dfrac{1}{2}:2-\sqrt{\left(-9\right)^2}\cdot\dfrac{1}{3}\right]\)
\(=\dfrac{9}{4}-\dfrac{1}{4}+9\cdot\dfrac{1}{3}\)
\(=\dfrac{8}{4}+3=3+2=5\)
20: \(\left(-0,5\right)^2\cdot8+\sqrt{\dfrac{9}{16}}:2\dfrac{1}{2}-\left|-\dfrac{3}{5}\right|\)
\(=0,25\cdot8+\dfrac{3}{4}:\dfrac{5}{2}-\dfrac{3}{5}\)
\(=2+\dfrac{3}{4}\cdot\dfrac{2}{5}-\dfrac{3}{5}\)
\(=\dfrac{7}{5}+\dfrac{3}{10}=\dfrac{14}{10}+\dfrac{3}{10}=\dfrac{17}{10}\)
21: \(\left|-\dfrac{5}{3}\right|:\sqrt{25}-1,12\cdot\sqrt{\dfrac{49}{36}}-1\dfrac{2}{7}\cdot\left(-\dfrac{14}{15}\right)\)
\(=\dfrac{5}{3}:5-1,12\cdot\dfrac{7}{6}-\dfrac{9}{7}\cdot\dfrac{-14}{15}\)
\(=\dfrac{1}{3}-\dfrac{98}{75}+\dfrac{6}{25}\)
\(=-\dfrac{11}{15}\)
22: \(\left(-\dfrac{5}{4}\right)^2\cdot0,16-\sqrt{\dfrac{4}{81}}:\dfrac{16}{9}+\left(-2018\right)^0\)
\(=\dfrac{25}{16}\cdot\dfrac{16}{100}-\dfrac{2}{9}\cdot\dfrac{9}{16}+1\)
\(=\dfrac{1}{4}-\dfrac{1}{8}+1=\dfrac{1}{8}+1=\dfrac{9}{8}\)
23: \(\left(-\dfrac{1}{3}\right)^2+\left(-\dfrac{1}{4}\right)^3\cdot64+\left(-\dfrac{2015}{2016}\right)^0\)
\(=\dfrac{1}{9}-\dfrac{1}{64}\cdot64+1\)
=1/9
24: \(\dfrac{1}{3}-\dfrac{1}{3}:\left(-\dfrac{2}{3}\right)^2+\left(-3\right)^3\left(7\dfrac{7}{9}-9\dfrac{2}{3}\right)\)
\(=\dfrac{1}{3}-\dfrac{1}{3}:\dfrac{4}{9}+\left(-27\right)\cdot\left(7+\dfrac{7}{9}-9-\dfrac{2}{3}\right)\)
\(=\dfrac{1}{3}-\dfrac{1}{3}\cdot\dfrac{9}{4}+\left(-27\right)\cdot\left(-2+\dfrac{1}{9}\right)\)
\(=\dfrac{1}{3}\cdot\dfrac{-5}{4}+\left(-27\right)\cdot\dfrac{-17}{9}\)
\(=-\dfrac{5}{12}+51=\dfrac{607}{12}\)
