`A=-3x+2\sqrt{x}+6`
`A=-3(x-2/3\sqrt{x}-2)`
`A=-3(x-2\sqrt{x}. 1/3+1/9-1/9)`
`A=-3(\sqrt{x}-1/3)^2+1/3`
Với `x >= 0<=>-3(\sqrt{x}-1/3)^2 <= 0`
`<=>-3(\sqrt{x}-1/3)^2+1/3 <= 1/3`
Hay `A <= 1/3`
Dấu "`=`" xảy ra `<=>(\sqrt{x}-1/3)^2=0<=>\sqrt{x}=1/3<=>x=1/9` (t/m)