đk x ≠1 ; x ≥ 0
\(=\dfrac{x+2}{\sqrt{x^3}-1}+\dfrac{\sqrt{x}}{x+\sqrt{x}+1}+\dfrac{-1}{\sqrt{x}-1}\\ =\dfrac{x+2+\sqrt{x}\left(\sqrt{x}-1\right)-x-\sqrt{x}-1}{\sqrt{x^3}-1}\\=\dfrac{x+2+x-\sqrt{x}-x-\sqrt{x}-1}{\sqrt{x^3}-1}\\ =\dfrac{x-2\sqrt{x}+1}{\sqrt{x^3}-1}\\ =\dfrac{\left(\sqrt{x}-1\right)^2}{\sqrt{x^3}-1}=\dfrac{\sqrt{x}-1}{x+\sqrt{x}+1} \)