a.b.\(n_{CH_3COOH}=1.0,2=0,2mol\)
\(2CH_3COOH+Zn\rightarrow\left(CH_3COO\right)_2Zn+H_2\)
0,2 0,2 0,2 ( mol )
\(V_{H_2}=0,2.24,79=4,958l\)
\(m_{Zn}=0,2.65=13g\)
c.\(CH_3COOH+C_2H_5OH\rightarrow\left(t^o,H_2SO_4\left(đ\right)\right)CH_3COOC_2H_5+H_2O\)
0,2 0,2 ( mol )
\(m_{CH_3COOC_2H_5}=0,2.88.80\%=14,08g\)