\(n_P=\dfrac{9.3}{31}=0.3\left(mol\right)\)
\(4P+5O_2\underrightarrow{^{t^0}}2P_2O_5\)
\(0.3.....0.375.....0.15\)
\(m_{P_2O_5}=0.15\cdot142=21,3\left(g\right)\)
\(2KClO_3\underrightarrow{^{t^0}}2KCl+3O_2\)
\(0.25......................0.375\)
\(m_{KClO_3}=0.25\cdot122.5=30.625\left(g\right)\)