Question

Answer 1

a.\(V_{O_2}=0,1.22,4=2,24l\)

b.\(V_{CH_4}=0,2.22,4=4,48l\)

c.\(V_{CO_2}=0,3.22,4=6,72l\)

d.\(V_{H_2}=\dfrac{4}{2}.22,4=44,8l\)

e.\(V_{N_2}=\dfrac{14}{28}.22,4=11,2l\)

f.\(V_{Cl_2}=\dfrac{7,1}{71}.22,4=2,24l\)

 

Answer 2

a.VO2=0,1.22,4=2,24lVO2=0,1.22,4=2,24l

b.VCH4=0,2.22,4=4,48lVCH4=0,2.22,4=4,48l

c.VCO2=0,3.22,4=6,72lVCO2=0,3.22,4=6,72l

d.VN2=1428.22,4=11,2lVN2=1428.22,4=11,2l

f.