Question

Answer 1

a: \(\Leftrightarrow2x-4=4\)

hay x=4

b: \(\Leftrightarrow\sqrt{x-1}=6\)

hay x=37

Answer 2

a) \(\sqrt{2x-4} = 2 \Leftrightarrow 2x-4=4 \Rightarrow x=4\)

b) \(\sqrt{16x-16} -3\sqrt{x-1}=0\) điều kiện x-1≥0 ⇒x≥1

\(\Leftrightarrow \sqrt{16(x-1)} - 3\sqrt{x-1}=0 \)

\(\Leftrightarrow 4\sqrt{x-1} -3\sqrt{x-1}=0 \)

\(\Leftrightarrow \sqrt{x-1}=0 \Rightarrow x-1=0 \Rightarrow x=1 (nhận) \)