\(\dfrac{1}{4}\sqrt{82}=\dfrac{\sqrt{82}}{4}=\dfrac{7\sqrt{82}}{28};6\sqrt{\dfrac{1}{7}}=\dfrac{6\sqrt{7}}{7}=\dfrac{24\sqrt{7}}{28}\\ 7\sqrt{82}=\sqrt{4018}< \sqrt{4032}=24\sqrt{7}\\ \Rightarrow\dfrac{7\sqrt{82}}{28}< \dfrac{24\sqrt{7}}{28}\\ \Rightarrow\dfrac{1}{4}\sqrt{82}< 6\sqrt{\dfrac{1}{7}}\)