\(\dfrac{9}{20}+\dfrac{8}{20}=\dfrac{9+8}{20}=\dfrac{17}{20}\)
\(\dfrac{13}{17}-\dfrac{3}{17}=\dfrac{13-3}{17}=\dfrac{10}{17}\)
\(\dfrac{9}{20}+\dfrac{8}{20}=\dfrac{9+8}{20}=\dfrac{17}{20}\)
\(\dfrac{13}{17}-\dfrac{3}{17}=\dfrac{13-3}{17}=\dfrac{10}{17}\)
\(\dfrac{7}{8}\cdot\dfrac{5}{7}=\dfrac{5}{8}\)
