Question

Answer 1

Ta có: \(\hat{AOC}-\hat{AOD}=20^0\)

mà \(\hat{AOC}+\hat{AOD}=180^0\) (hai góc kề bù)

nên \(\hat{AOC}=\frac{20^0+180^0}{2}=100^0;\hat{AOD}=100^0-20^0=80^0\)

Ta có: \(\hat{AOC}=\hat{BOD}\) (hai góc đối đỉnh)

mà \(\hat{AOC}=100^0\)

nên \(\hat{BOD}=100^0\)

Ta có: \(\hat{AOD}=\hat{BOC}\) (hai góc đối đỉnh)

mà \(\hat{AOD}=80^0\)

nên \(\hat{BOC}=80^0\)