Question

Answer 1

1/ \(\left\{{}\begin{matrix}2Z+N=34\\Z=32,36\%.34\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}Z=11=P=E\\N=12\end{matrix}\right.\)

Vì Z=11 => X là Natri (Na)

2/\(\left\{{}\begin{matrix}2Z+N=82\\2Z-N=22\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}Z=26=P=E\\N=30\end{matrix}\right.\)

Vì Z=26 => R là Sắt (Fe)

3/ \(\left\{{}\begin{matrix}2Z+N=115\\2Z=1,556N\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}Z=35\\N=45\end{matrix}\right.\)

Vì Z=35 => Y là Brom (Br)