e) PT \(\Leftrightarrow\left|\dfrac{2}{3}x+\dfrac{3}{5}\right|=-\dfrac{17}{8}\) \(\Leftrightarrow x\in\varnothing\)
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f) PT \(\Leftrightarrow\left|\dfrac{2}{3}-x\right|=2\dfrac{1}{3}-75\%=\dfrac{19}{12}\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{2}{3}-x=\dfrac{19}{12}\\x-\dfrac{2}{3}=\dfrac{19}{12}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{11}{12}\\x=\dfrac{9}{4}\end{matrix}\right.\)
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g) PT \(\Leftrightarrow\left(x+\dfrac{1}{3}\right)^2=9\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=3\\x+\dfrac{1}{3}=-3\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{8}{3}\\x=-\dfrac{10}{3}\end{matrix}\right.\)
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h) PT \(\Leftrightarrow\left[{}\begin{matrix}x-1\dfrac{2}{3}=0\\25\%-x=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=1\dfrac{2}{3}=\dfrac{5}{3}\\x=25\%=\dfrac{1}{4}\end{matrix}\right.\)
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