HOC24
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Chủ đề / Chương
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\(\left(x^2-y^2+6x+9\right):\left(x+y+3\right)\)
\(=\text{[}\left(x^2+6x+9\right)-y^2\text{]}:\left(x+y+3\right)\)
\(=\text{[}\left(x+3\right)^2-y^2\text{]}:\left(x+y+3\right)\)
\(=\left(x+3+y\right)\left(x+3-y\right):\left(x+y+3\right)\)
\(=x+3-y\)
1, \(x^2-y^2-x-y=\left(x-y\right)\left(x+y\right)-\left(x+y\right)\)
=\(\left(x+y\right)\left(x-y-1\right)\)
2, \(x^4-5x^2+4=x^4-4x^2-x^2+4\)
\(=x^2\left(x^2-4\right)-\left(x^2-4\right)\)
\(=\left(x^2-4\right)\left(x^2-1\right)\)
\(=\left(x-2\right)\left(x+2\right)\left(x-1\right)\left(x+1\right)\)
3, \(25-x^2+2xy-y^2=5^2-\left(x^2-2xy+y^2\right)\)
\(=5^2-\left(x-y\right)^2\)
\(=\left(5-x+y\right)\left(5+x-y\right)\)