\(\dfrac{x+5}{100}+\dfrac{x+4}{101}=\dfrac{x+3}{102}+\dfrac{x+2}{103}\)

<=> \(\left(\dfrac{x+5}{100}+1\right)+\left(\dfrac{x+4}{101}+1\right)=\left(\dfrac{x+3}{102}+1\right)+\left(\dfrac{x+2}{103}+1\right)\)

<=> \(\dfrac{x+105}{100}+\dfrac{x+105}{101}-\dfrac{x+105}{102}-\dfrac{x+105}{103}=0\)

<=> \(\left(x+105\right)\left(\dfrac{1}{100}+\dfrac{1}{101}-\dfrac{1}{102}-\dfrac{1}{103}\right)=0\)

<=> x + 105 = 0

<=> x = -105

(4) CaCO₃ + 2HCl ---> CaCl₂ + CO₂ + H₂O

BT1:

(1) Ca(OH)₂ + CO₂ ---> CaCO₃↓ + H₂O

(2) CaCO₃ ---t^o---> CaO + CO₂.

(3) CaO + 2HCl ---> CaCl₂ + H₂O

(4) CaCO₃ + HCl ---> CaCl₂ + CO₂ + H₂O.

:v

Bn nên chia đề ra để mn dễ làm