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Đề đâu bn nhỉ

= \(\dfrac{2}{5}\)

(8x - 16)(x - 5) = 0

<=> 8(x - 2)(x - 5) = 0

<=> \(\left[{}\begin{matrix}x-2=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=5\end{matrix}\right.\)

Ko có gì

Bài 2:

a. 8x(5x - 2) - 12(5x - 2) = 0

<=> (8x - 12)(5x - 2) = 0

<=> \(\left[{}\begin{matrix}8x-12=0\\5x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{5}{2}\end{matrix}\right.\)

\(\dfrac{2}{3}x-\dfrac{2}{5}=\dfrac{1}{2}x-\dfrac{1}{3}\)

<=> \(\dfrac{2}{3}x-\dfrac{1}{2}x=\dfrac{2}{5}-\dfrac{1}{3}\)

<=> \(\dfrac{1}{6}x=\dfrac{1}{15}\)

<=> 15x = 6

<=> x = \(\dfrac{6}{15}\)