chắc ko phải

câu trả lời đâu rồi ?

\(\dfrac{5}{12}.\dfrac{4}{11}-\dfrac{4}{11}+\dfrac{7}{12}.\dfrac{4}{11}\)

\(=\dfrac{4}{11}.\left(\dfrac{5}{12}-1+\dfrac{7}{12}\right)\)

\(=\dfrac{4}{11}.\left(\dfrac{5}{12}-\dfrac{12}{12}+\dfrac{7}{12}\right)\)

\(=\dfrac{4}{11}.\left(\dfrac{-7}{12}+\dfrac{7}{12}\right)\)

\(=\dfrac{4}{11}.\dfrac{0}{12}\)

\(=\dfrac{4}{11}.0\)

\(=0\)

\(\dfrac{2}{5}\times\dfrac{5}{7}\times\dfrac{7}{9}:\dfrac{1}{9}\)

\(=\dfrac{2\times5}{5\times7}\times\dfrac{7}{9}:\dfrac{1}{9}\)

\(=\dfrac{2\times1}{1\times7}\times\dfrac{7}{9}:\dfrac{1}{9}\)

\(=\dfrac{2}{7}\times\dfrac{7}{9}:\dfrac{1}{9}\)

\(=\dfrac{2\times7}{7\times9}:\dfrac{1}{9}\)

\(=\dfrac{2\times1}{1\times9}:\dfrac{1}{9}\)

\(=\dfrac{2}{9}:\dfrac{1}{9}\)

\(=\dfrac{2}{9}\times\dfrac{9}{1}\)

\(=\dfrac{2\times9}{9\times1}\)

\(=\dfrac{2\times1}{1\times1}\)

\(=\dfrac{2}{1}\)

\(=2\)

1.listen

2. rains

3.will recognise

4.don't want

5. will/ begin

6.won't be

7.does/ watchs

8.will plant

9.play

10.leaves

câu 10 là tidying nha mik ghi lộn

1. going

2.playing

3.taking

4.watching

5.cooking

6.making

7.tiding

\(\dfrac{3}{7}.\left(\dfrac{13}{8}-\dfrac{7}{9}\right)-\dfrac{5}{8}.\left(\dfrac{3}{7}-\dfrac{8}{15}\right)\)

\(=\dfrac{3}{7}.\dfrac{13}{8}-\dfrac{3}{7}.\dfrac{7}{9}-\dfrac{5}{8}.\dfrac{3}{7}-\dfrac{5}{8}.\dfrac{8}{15}\)

\(=\dfrac{3}{7}.\left(\dfrac{13}{8}-\dfrac{5}{8}\right)-\dfrac{3.7}{7.9}-\dfrac{5.8}{8.15}\)

\(=\dfrac{3}{7}.\dfrac{8}{8}-\dfrac{1.1}{1.3}-\dfrac{1.1}{1.3}\)

\(=\dfrac{3}{7}.1-\dfrac{1}{3}-\dfrac{1}{3}\)

\(=\dfrac{3}{7}-\dfrac{1}{3}-\dfrac{1}{3}\)

\(=\dfrac{3}{7}-\left(\dfrac{1}{3}-\dfrac{1}{3}\right)\)

\(=\dfrac{3}{7}-0\)

\(=\dfrac{3}{7}\)

tia phân giác là tia nằm giữa 2 cạnh của góc và tạo vs 2 cạnh ấy bằng 2 góc bằng nhau

bài đâu rồi