c) \(\dfrac{3x-1}{x-1}-\dfrac{2x+5}{x+3}-\dfrac{8}{x^2+2x-3}=1\)
\(\Leftrightarrow\dfrac{3x-1}{x-1}-\dfrac{2x+5}{x+3}-\dfrac{8}{x^2-1x+3x-3}=1\)
\(\Leftrightarrow\dfrac{3x-1}{x-1}-\dfrac{2x+5}{x+3}-\dfrac{8}{x\left(x-1\right)+3\left(x-1\right)}=1\)
\(\Leftrightarrow\dfrac{\left(x+3\right)\left(3x-1\right)}{\left(x-1\right)\left(x+3\right)}-\dfrac{\left(x-1\right)\left(2x+5\right)}{\left(x-1\right)\left(x+3\right)}-\dfrac{8}{\left(x+3\right)\left(x-1\right)}=1\)
\(\Leftrightarrow\left(x+3\right)\left(3x-1\right)-\left(x-1\right)\left(2x+5\right)-8-1=0\)
\(\Leftrightarrow3x^2-x+9x-3-\left(2x^2+5x-2x-5\right)-9=0\)
\(\Leftrightarrow3x^2-x+9x-3-2x^2-5x+2x+5-9=0\)
\(\Leftrightarrow\left(3x^2-2x^2\right)+\left(-x+9x-5x+2x\right)+\left(-3+5-9\right)=0\)
\(\Leftrightarrow x^2+5x-7=0\)
còn lại bạn tham khảo ở đây nhé: https://hoc24.vn/cau-hoi/x2-5x-7-0.260367740520
Kết luận: x vô nghiệm.

90^o

1) (1-2x)(3x+2)=0
\(\Leftrightarrow\left[{}\begin{matrix}1-2x=0\\3x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{-2}{3}\end{matrix}\right.\)
vậy ...
2) (3x-1)\(\left[\dfrac{2\left(x-3\right)}{3}-\dfrac{x+1}{4}\right]=0\)   
\(\left(3x-1\right)\left[\dfrac{8\left(x-3\right)}{12}-\dfrac{3\left(x+1\right)}{12}\right]=0\)
\(\left(3x-1\right)\left(\dfrac{8x-24-3x-3}{12}\right)=0\)
\(\left(3x-1\right)\left(\dfrac{5x-21}{12}\right)=0\)
Th1: 3x-1=0       Th2: (5x-21):12=0
         3x=1                        5x-21=0
           x=\(\dfrac{1}{3}\)                          5x=21
                                               x=\(\dfrac{21}{5}\)
Vậy ...

xét nghiệm
âm tính
không bị

e mang được 8,0 điểm trung bình về cho mẹ:))