1 x 5 x 6 = 5 x 6 = 30

4+ 5 - 6

​= 9 - 6

​= 3

\(\left(x^2-2x+1\right)-4=0\)

\(x^2-x-x+1=4\)

\(x.\left(x-1\right)-\left(x-1\right)=4\)

\(\left(x-1\right)^2=4\)

=> \(\orbr{\begin{cases}x-1=2\\x-1=-2\end{cases}}\)=> \(\orbr{\begin{cases}x=3\\x=-1\end{cases}}\)

x-11=22

x      =22+11

x      =33

Tính:

a) \(A=\sqrt[3]{70-\sqrt{4901}}+\sqrt[3]{70+\sqrt{4901}}\)

b) \(B=\frac{1}{\sqrt[3]{6}+\sqrt[3]{4}+\sqrt[3]{9}}+\sqrt[3]{2}\)